[Solved] Typeerror: not all arguments converted during string formatting

Hello readers, Today In this article I am going to show you how to solve – Typeerror: not all arguments converted during string formatting error in Python. So Here I will explain all the possible solutions.

Without wasting your time, Let’s start This Article to Solve This Error.

How to Typeerror: not all arguments converted during string formatting Occurs?

This is a common error to operation or use function on an object of a different type you might face while running a Python application. It looks as like below:

Traceback (most recent call last):
  File "program.py", line 13, in <module>
    print ("'{0}' is longer than '{1}'"% name1, name2)
TypeError: not all arguments converted during string formatting

How To Solve Typeerror: not all arguments converted during string formatting Error?

• How To Solve TypeError: not all arguments converted during string formatting Error ?

To Solve TypeError: not all arguments converted during string formatting Error The new-style if you are using {} then You have to use .format method. Second solution old-style is For String formatting Use the % operator is to use a printf-style format string. Now, I hope your error must be solved.

• TypeError: not all arguments converted during string formatting

To Solve TypeError: not all arguments converted during string formatting Error The new-style if you are using {} then You have to use .format method. Second solution old-style is For String formatting Use the % operator is to use a printf-style format string. Now, I hope your error must be solved.

Solution 1: use the ‘%’ operator

For string formatting using the ‘%’ operator is to use a printf-style format string.

"'%s' is longer than '%s'" % (name1, name2)

Now, I hope your error will be solved.

Solution 2: use .format

If you are using {} format specifiers, then you have to use .format Just like this.

"'{0}' is longer than '{1}'".format(name1, name2)

Now, I hope second way will be solved the error.

Solution 3: Use f-strings

There is a new and easy way to call f-strings. Here is the syntax.

name = "Eric"
age = 74
f"Hello, {name}. You are {age}."

Output:

Hello, Eric. You are 74.

The third way I hope will be solved the error.

Summary

It’s all About this issue. Hope all solution helped you a lot. Comment below Your thoughts and your queries. Also, Comment below which solution worked for you?